What is the sum of the distinct prime factors of 735?

Factors of 735 are integers that can be divided evenly into 735. There are 12 factors of 735 of which 735 itself is the biggest factor and its prime factors are 3, 5, 7 The sum of all factors of 735 is 1368.

Is 1 a distinct prime factor?

When n is a prime number, the prime factorization is just n itself, written in bold below. The number 1 is called a unit. It has no prime factors and is neither prime nor composite.

How to calculate the sum of all factors of a number?

// This code is contributed by SanjuTomar. An efficient solution is to use below formula. Let p 1, p 2, … p k be prime factors of n. Let a 1, a 2, .. a k be highest powers of p 1, p 2, .. p k respectively that divide n, i.e., we can write n as n = (p1a1)* (p2a2)* … (pkak).

How to find the sum of a sequence?

To do this, add the two numbers, and divide by 2. Multiply the average by the number of terms in the series. This will give you the sum of the arithmetic sequence. So, the sum of the sequence 10, 15, 20, 25, 30 is 100. Find the sum of numbers between 1 and 500. Consider all consecutive integers. {\displaystyle n}) in the sequence.

How to find the sum of prime numbers up to a prime number?

Closed 7 years ago. How to find the sum of prime numbers up to a prime number n, that is for example: the sum of prime numbers up to 7 is: 2+3+5+7=17. ∑ k = 0 n p k =????, with p k being the k th prime. Also if we have the sum of an even number of primes then would it be a new prime?

How many primes are in an even integer?

It has been proven that every even integer is the sum of at most six primes [Ramaré95] (Goldbach’s conjecture suggests two) and in 1966 Chen proved every sufficiently large even integer is the sum of a prime plus a number with no more than two prime factors (a P2).